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=Y^2-180Y-30
We move all terms to the left:
-(Y^2-180Y-30)=0
We get rid of parentheses
-Y^2+180Y+30=0
We add all the numbers together, and all the variables
-1Y^2+180Y+30=0
a = -1; b = 180; c = +30;
Δ = b2-4ac
Δ = 1802-4·(-1)·30
Δ = 32520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32520}=\sqrt{4*8130}=\sqrt{4}*\sqrt{8130}=2\sqrt{8130}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-2\sqrt{8130}}{2*-1}=\frac{-180-2\sqrt{8130}}{-2} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+2\sqrt{8130}}{2*-1}=\frac{-180+2\sqrt{8130}}{-2} $
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